t^2=42.25

Solution for t^2=42.25 equation:

t^2=42.25

We move all terms to the left:

t^2-(42.25)=0

We add all the numbers together, and all the variables

t^2-42.25=0

a = 1; b = 0; c = -42.25;
Δ = b2-4ac
Δ = 02-4·1·(-42.25)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-13}{2*1}=\frac{-13}{2}
=-6+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+13}{2*1}=\frac{13}{2}
=6+1/2
$